C memcpy() Function
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C memcpy() Function
The memcpy() function copies a block of memory from a location to another.
This function copies the data directly from source to destination. So, memcpy() is faster approach than memmove().
This function overlaps the source. So, memmove() is not as safe as memmove().
Example
C Compiler
#include <stdio.h>
#include <string.h>
int main()
{
char dest[] = "abcde";
char src[] = "123";
memcpy(dest, src, 3);
printf("New dest = %s", dest);
return 0;
}
Output
New dest = 123de
Syntax
void *memcpy(void *dest, const void *src, size_t n)
Parameter Values
| Value | Type | Explanation |
|---|---|---|
| dest | Required | Destination array where the content is to be copied. |
| src | Required | Source of data to be copied. |
| n | Required | Number of bytes to be copied. |
Return Value
| Value | Explanation |
|---|---|
| Address | Returns a pointer to the destination, which is dest array. |
More Examples
Example
C Compiler
#include <stdio.h>
#include <string.h>
int main()
{
char str1[] = "abcde";
memcpy(&str1[2], &str1[0], 3);
printf("New str1 = %s", str1);
return 0;
}
Output
New str1 = ababc
Example
C Compiler
#include <stdio.h>
#include <string.h>
int main()
{
char str1[] = "abcde";
char str2[] = "abcde";
memcpy(&str1[2], &str1[0], 3);
memmove(&str2[2], &str2[0], 3);
printf("memcpy's str1 = %s\n", str1);
printf("memmove's str2 = %s", str2);
return 0;
}
Output
memcpy's str1 = ababc
memmove's str2 = ababc
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