C memcpy() Function

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C memcpy() Function

The memcpy() function copies a block of memory from a location to another.

This function copies the data directly from source to destination. So, memcpy() is faster approach than memmove().

This function overlaps the source. So, memmove() is not as safe as memmove().


C Compiler
#include <stdio.h> #include <string.h> int main() { char dest[] = "abcde"; char src[] = "123"; memcpy(dest, src, 3); printf("New dest = %s", dest); return 0; }


New dest = 123de


void *memcpy(void *dest, const void *src, size_t n)

Parameter Values

destRequiredDestination array where the content is to be copied.
srcRequiredSource of data to be copied.
nRequiredNumber of bytes to be copied.

Return Value

AddressReturns a pointer to the destination, which is dest array.

More Examples


C Compiler
#include <stdio.h> #include <string.h> int main() { char str1[] = "abcde"; memcpy(&str1[2], &str1[0], 3); printf("New str1 = %s", str1); return 0; }


New str1 = ababc


C Compiler
#include <stdio.h> #include <string.h> int main() { char str1[] = "abcde"; char str2[] = "abcde"; memcpy(&str1[2], &str1[0], 3); memmove(&str2[2], &str2[0], 3); printf("memcpy's str1 = %s\n", str1); printf("memmove's str2 = %s", str2); return 0; }


memcpy's str1 = ababc memmove's str2 = ababc


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