C memcpy() Function

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C memcpy() Function

The memcpy() function copies a block of memory from a location to another.

This function copies the data directly from source to destination. So, memcpy() is faster approach than memmove().

This function overlaps the source. So, memmove() is not as safe as memmove().

Example

C Compiler
#include <stdio.h> #include <string.h> int main() { char dest[] = "abcde"; char src[] = "123"; memcpy(dest, src, 3); printf("New dest = %s", dest); return 0; }

Output

New dest = 123de

Syntax

void *memcpy(void *dest, const void *src, size_t n)

Parameter Values

ValueTypeExplanation
destRequiredDestination array where the content is to be copied.
srcRequiredSource of data to be copied.
nRequiredNumber of bytes to be copied.

Return Value

ValueExplanation
AddressReturns a pointer to the destination, which is dest array.

More Examples

Example

C Compiler
#include <stdio.h> #include <string.h> int main() { char str1[] = "abcde"; memcpy(&str1[2], &str1[0], 3); printf("New str1 = %s", str1); return 0; }

Output

New str1 = ababc

Example

C Compiler
#include <stdio.h> #include <string.h> int main() { char str1[] = "abcde"; char str2[] = "abcde"; memcpy(&str1[2], &str1[0], 3); memmove(&str2[2], &str2[0], 3); printf("memcpy's str1 = %s\n", str1); printf("memmove's str2 = %s", str2); return 0; }

Output

memcpy's str1 = ababc memmove's str2 = ababc

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