Python Number Pattern 35

You are Here:

Python Number Pattern 35

Try to print the following number pattern using Python.

Print This Output
             1
          2  3
       4  5  6
    7  8  9 10
11 12 13 14 15

Source Code

Python Compiler
k = 0 for i in range(1, 6): for j in range(5, 0, -1): if(j > i): print(" %2s" % (" "), end="") else: k += 1 print(" %2d" % (k), end="") print()

Output

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

Reminder

Hi Developers, we almost covered 90% of String functions and Interview Question on Python with examples for quick and easy learning.

We are working to cover every Single Concept in Python.

Please do google search for:

Join Our Channel

Join our telegram channel to get an instant update on depreciation and new features on HTML, CSS, JavaScript, jQuery, Node.js, PHP and Python.

This channel is primarily useful for Full Stack Web Developer.

Share this Page

Meet the Author