C++ Program to Swap Two Numbers

February 8, 2021 9:55 am IST

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C++ Program to Swap Two Numbers

In programming, there are two different techniques to swap any two numbers in a variable, they are

Swap using Temporary Variable
Swap without using Temporary Variable

Swap using Temporary Variable

In the following example, we will swap two numbers (25 and 50) using a temporary variable (temp).

Example

C++ Compiler

#include <iostream> using namespace std; int main() { int num1 = 25; int num2 = 50; int temp = 0; temp = num1; num1 = num2; num2 = temp; cout << "After swapping..."; cout << "\nnum1 = " << num1; cout << "\nnum2 = " << num2; return 0; }

Output

After swapping... num1 = 50 num2 = 25

Swap without using Temporary Variable

In the following example, we will swap two numbers (25 and 50) without using a temporary variable.

Example

C++ Compiler

#include <iostream> using namespace std; int main() { int num1 = 25; int num2 = 50; num1 = num1 - num2; num2 = num1 + num2; num1 = num2 - num1; cout << "After swapping..."; cout << "\nnum1 = " << num1; cout << "\nnum2 = " << num2; return 0; }

Output

After swapping... num1 = 50 num2 = 25

Swap any Two Given Numbers

In the following example, we will swap any two given numbers without using a temporary variable (temp).

Example

C++ Compiler

#include <iostream> using namespace std; int main() { int num1, num2, temp = 0; cout << "Enter (int) Number1: "; cin >> num1; cout << "Enter (int) Number2: "; cin >> num2; temp = num1; num1 = num2; num2 = temp; cout << "\nAfter swapping..."; cout << "\nnum1 = " << num1; cout << "\nnum2 = " << num2; return 0; }