C++ Program to Check Palindrome Number

February 8, 2021 9:55 am IST

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What is Palindrome Number?

A palindrome number is a number that remains the same when its digits are reversed. For example, 55 is a palindrome number.

Note: The reverse of 55 is also a 55. Hence, 55 is a palindrome number.

Tips: It is recommended to use our online Palindrome Numbers calculator for better understanding.

Check Palindrome Number

In the following example, we will check whether the given number (121) is a Palindrome number or not.

Example

C++ Compiler

#include <iostream> using namespace std; int main() { int num = 121; int copyNum = num; int reverse = 0; // reverse a number while(copyNum != 0) { reverse = reverse * 10; reverse = reverse + (copyNum % 10); copyNum = copyNum / 10; } // result if(num == reverse) cout << num << " is a palindrome number"; else cout << num << " is not a palindrome number"; return 0; }

Output

121 is a palindrome number

Palindrome Numbers between the Given Range

In the following example, we will find all the Palindrome numbers between 10 and 50.

Example

C++ Compiler

#include <iostream> using namespace std; int main() { int start = 10; int end = 50; int copyNum = 0; int reverse = 0; int flag = 0; cout << "Palindrome numbers between " << start << " and " << end << ":\n"; for(start=start; start<=end; start++) { copyNum = start; reverse = 0; // reverse a number while(copyNum != 0) { reverse = reverse * 10; reverse = reverse + (copyNum % 10); copyNum = copyNum / 10; } // result if((start == reverse) && (start != 0)) { flag = 1; cout << start << " "; } } if(flag == 0) cout << "There is no palindrome number between the given range"; return 0; }

Output

Palindrome numbers between 10 and 50: 11 22 33 44

Check Whether the Given Number is Palindrome or Not

In the following example, we will check whether the given number is a Palindrome Number or Not.

Example

C++ Compiler

#include <iostream> using namespace std; int main() { int num, reverse = 0; cout << "Enter a (int) Number: "; cin >> num; int copyNum = num; // reverse a number while(copyNum != 0) { reverse = reverse * 10; reverse = reverse + (copyNum % 10); copyNum = copyNum / 10; } // result if(num == reverse) cout << num << " is a palindrome number"; else cout << num << " is not a palindrome number"; return 0; }