C++ Program to Check Even Number

You are Here:

What are Even Numbers?

An integer (never a fraction) that can be divided exactly by 2. For example, 10 is an even number, i.e., 10 % 2 = 0.

Note: % is a Modulus (Division Remainder) operator, it finds the remainder after division of one number by another. Please check our Arithmetic Operators for more details.

Tips: It is recommended to use our online Even Numbers calculator for better understanding.

Using For Loop

In the following example, we will find all the Even Numbers between 10 and 25 using for loop.

Example

C++ Compiler
#include <iostream> using namespace std; int main() { int start = 10; int end = 25; cout << "Even numbers between " << start << " and " << end << ":\n"; for(start=start; start<=end; start++) { if(start % 2 == 0) cout << start << " "; } return 0; }

Output

Even numbers between 10 and 25: 10 12 14 16 18 20 22 24

Using While Loop

In the following example, we will find all the Even Numbers between 10 and 25 using while loop.

Example

C++ Compiler
#include <iostream> using namespace std; int main() { int start = 10; int end = 25; cout << "Even numbers between " << start << " and " << end << ":\n"; while(start <= end) { if(start % 2 == 0) cout << start << " "; start++; } return 0; }

Output

Even numbers between 10 and 25: 10 12 14 16 18 20 22 24

Using do while Loop

In the following example, we will find all the Even Numbers between 10 and 25 using do while loop.

Example

C++ Compiler
#include <iostream> using namespace std; int main() { int start = 10; int end = 25; cout << "Even numbers between " << start << " and " << end << ":\n"; do{ if(start % 2 == 0) cout << start << " "; start++; }while(start <= end); return 0; }

Output

Even numbers between 10 and 25: 10 12 14 16 18 20 22 24

Even Numbers between any Given Range

In the following example, we will find all the Even numbers between any given range.

Example

C++ Compiler
#include <iostream> using namespace std; int main() { int start, end; cout << "Enter a (int) starting number: "; cin >> start; cout << "Enter an (int) ending number: "; cin >> end; cout << "\nEven numbers between " << start <<" and " << end <<":\n"; for(start=start; start<=end; start++) { if(start % 2 == 0) cout << start << " "; } return 0; }

Output

Enter a (int) starting number: 5 Enter an (int) ending number: 10 Even numbers between 5 and 10: 6 8 10

Check Whether the Given Number is Even or Odd

In the following example, we will check whether the given number is an Even number or Odd number.

Example

C++ Compiler
#include <iostream> using namespace std; int main() { int num; cout << "Enter a (int) number: "; cin >> num; if(num % 2 == 0) cout << num << " is an even number"; else cout << num << " is an odd number"; return 0; }

Output

Enter a (int) number: 16 16 is an even number

Reminder

Hi Developers, we almost covered 90% of String functions and Interview Question on C++ with examples for quick and easy learning.

We are working to cover every Single Concept in C++.

Please do google search for:

Join Our Channel

Join our telegram channel to get an instant update on depreciation and new features on HTML, CSS, JavaScript, jQuery, Node.js, PHP and Python.

This channel is primarily useful for Full Stack Web Developer.

Share this Page

Meet the Author