C# Program to Swap Two Numbers

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C# Program to Swap Two Numbers

In programming, there are two different techniques to swap any two numbers in a variable, they are

  • Swap using Temporary Variable
  • Swap without using Temporary Variable

Swap using Temporary Variable

In the following example, we will swap two numbers (25 and 50) using a temporary variable (temp).

Example

C# Compiler
using System; namespace myApp { class Program { static void Main(string[] args) { int num1 = 25; int num2 = 50; int temp = 0; temp = num1; num1 = num2; num2 = temp; Console.WriteLine("After swapping..."); Console.WriteLine("num1 = {0}", num1); Console.WriteLine("num2 = {0}", num2); } } }

Output

After swapping... num1 = 50 num2 = 25

Swap without using Temporary Variable

In the following example, we will swap two numbers (25 and 50) without using a temporary variable.

Example

C# Compiler
using System; namespace myApp { class Program { static void Main(string[] args) { int num1 = 25; int num2 = 50; num1 = num1 - num2; num2 = num1 + num2; num1 = num2 - num1; Console.WriteLine("After swapping..."); Console.WriteLine("num1 = {0}", num1); Console.WriteLine("num2 = {0}", num2); } } }

Output

After swapping... num1 = 50 num2 = 25

Swap any Two Given Numbers

In the following example, we will swap any two given numbers without using a temporary variable (temp).

Example

C# Compiler
using System; namespace myApp { class Program { static void Main(string[] args) { int temp = 0; Console.Write("Enter (int) Number1: "); int num1 = Convert.ToInt32(Console.ReadLine()); Console.Write("Enter (int) Number2: "); int num2 = Convert.ToInt32(Console.ReadLine()); temp = num1; num1 = num2; num2 = temp; Console.WriteLine("\nAfter swapping..."); Console.WriteLine("num1 = {0}", num1); Console.WriteLine("num2 = {0}", num2); } } }

Output

Enter (int) Number1: 25 Enter (int) Number2: 36 After swapping... num1 = 36 num2 = 25

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